Answer a question

I'm newbie in parsing tables and regular expressions, can you help to parse this in python:

<table callspacing="0" cellpadding="0">
    <tbody><tr>
    <td>1text&nbsp;2text</td>
    <td>3text&nbsp;</td>
    </tr>
    <tr>
    <td>4text&nbsp;5text</td>
    <td>6text&nbsp;</td>
    </tr>
</tbody></table>

I need the "3text" and "6text"

Answers

You can use CSS selector select() and select_one() to get "3text" and "6text" like below:

import requests
from bs4 import BeautifulSoup
html_doc='''
<table callspacing="0" cellpadding="0">
    <tbody><tr>
    <td>1text&nbsp;2text</td>
    <td>3text&nbsp;</td>
    </tr>
    <tr>
    <td>4text&nbsp;5text</td>
    <td>6text&nbsp;</td>
    </tr>
</tbody></table>
'''

soup = BeautifulSoup(html_doc, 'lxml')
soup1 = soup.select('tr')

for i in soup1:
    print(i.select_one('td:nth-child(2)').text)

You can also use find_all method:

trs = soup.find('table').find_all('tr')

for i in trs:
    tds = i.find_all('td')
    print(tds[1].text)

Result:

3text 
6text