Answer a question

The HTML looks

<p class="rating item-rating">
<picture>
<source srcset="/assets/img/ratings/rating-4_5.svg" type="image/svg+xml"/>
<img src="/assets/img/ratings/rating-4_5.png"/>
</picture>
<span>
260
</span>
</p>

And I would like to get

/assets/img/ratings/rating-4_5.png

How should I improve the following code?

img = soup.findAll('p',attrs={'class':'rating item-rating'})

for i in img:
    print(i.picture)

Answers

You need to get to the img tag as that seems to hold the information you want in the src attribute.

from bs4 import BeautifulSoup

s = '''<p class="rating item-rating">
<picture>
<source srcset="/assets/img/ratings/rating-4_5.svg" type="image/svg+xml"/>
<img src="/assets/img/ratings/rating-4_5.png"/>
</picture>
<span>
260
</span>
</p>'''

soup = BeautifulSoup(s, 'html.parser')
for p in soup.select('p.rating'):
    print(p.picture.img['src'])