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I face a problem which I can't find a solution for. I have a button in navbar which is available on all pages and it is a button responsible for creating some content.

View that links with button:

def createadv(request):
    uw = getuw(request.user.username)
    if request.method =='POST':
    form = AdverForm(request.POST, request.FILES)
    if form.is_valid():
        form.instance.user = request.user
        form.save()
        return HttpResponseRedirect('/', {'username': request.user.username, 'uw': uw})
    args = {}
    args.update(csrf(request))
    args['username'] = request.user.username
    args['form'] = AdverForm()
    args['uw'] = uw
    return  render_to_response('createadv.html', args)

If you can see now I always redirect to main page '/' after creating content but I want to go back to the page with which I launched the creation of content.

Answers

You can add a next field to your form, and set it to request.path. After you processed your form you can redirect to the value of this path.

template.html

<form method="POST">
    {% csrf_token %}
    {{ form }}
    <input type="hidden" name="next" value="{{ request.path }}">
    <button type="submit">Let's Go</button>
</form>

views.py

next = request.POST.get('next', '/')
return HttpResponseRedirect(next)

This is roughly what django.contrib.auth does for the login form if I remember well.

If you pass through an intermediate page, you can pass the 'next' value via the querystring:

some_page.html

<a href="{% url 'your_form_view' %}?next={{ request.path|urlencode }}">Go to my form!</a>

template.html

<form method="POST">
    {% csrf_token %}
    {{ form }}
    <input type="hidden" name="next" value="{{ request.GET.next }}">
    <button type="submit">Let's Go</button>
</form>