Django order_by() filter with distinct()
Answer a question How can I make an order_by like this .... p = Product.objects.filter(vendornumber='403516006')\ .order_by('-created').distinct('vendor__name') The problem is that I have multiple ven
Answer a question
How can I make an order_by
like this ....
p = Product.objects.filter(vendornumber='403516006')\
.order_by('-created').distinct('vendor__name')
The problem is that I have multiple vendors with the same name, and I only want the latest product by the vendor ..
Hope it makes sense?
I got this DB error:
SELECT DISTINCT ON expressions must match initial ORDER BY expressions LINE 1: SELECT DISTINCT ON ("search_vendor"."name") "search_product"...
Answers
Based on your error message and this other question, it seems to me this would fix it:
p = Product.objects.filter(vendornumber='403516006')\
.order_by('vendor__name', '-created').distinct('vendor__name')
That is, it seems that the DISTINCT ON
expression(s) must match the leftmost ORDER BY
expression(s). So by making the column you use in distinct
as the first column in the order_by
, I think it should work.
更多推荐
所有评论(0)