【C++】封装红黑树实现mymap和myset
整体框架分析

- 对SGI-STL30版本源代码的框架进行分析,可以看到rb_tree⽤了⼀个巧妙的泛型思想实现,rb_tree是实现key的搜索场景,还是key/value的搜索场景不是直接写死的,而是由第二个模板参数Value决定红黑树结点中存储的真实的数据的类型。
- 那么,set实例化rb_tree时第二个模板参数给的是key,map实例化rb_tree时第二个模板参数给的是pair<const key,T>,这样⼀颗红黑树既可以实现key搜索场景的set,也可以实现key/value搜索场景的map。
- rb_tree第二个模板参数Value已经控制了红黑树结点中存储的数据类型,为什么还要传第⼀个模板参数Key呢?对于map和set,find/erase时的函数参数都是Key,所以第⼀个模板参数是传给find/erase等函数做形参的类型的。对于set而言两个参数是⼀样的,但是对于map而言就完全不⼀样了,map insert的是pair对象,但是find和erase的是Key对象。
模拟实现map和set思路
实现复用红黑树的框架
- 参考源码框架,map和set复用之前我实现的红黑树。
- 这里相比源码调整⼀下,key参数就用K,value参数就用V,红黑树中的数据类型,我们使用T。
- 在insert内部进行插入逻辑比较时,因为不知道比较的是K,还是pair<K,V>,且pair的默认支持的是key和value⼀起参与比较,这和我们需要的任何时候只比较key的需求不符,所以参考源码中的思路,我们在map和set层分别实现⼀个MapKeyOfT和SetKeyOfT的仿函数传给RBTree的KeyOfT,然后RBTree中通过KeyOfT仿函数取出T类型对象中的key,再进行比较。
下面通过代码展示实现细节
myset.h
#include"RBTree.h"
namespace highcool
{
template<class K>
class set
{
struct SetKeyOfT
{
const K& operator()(const K& key)
{
return key;
}
};
public:
bool insert(const K& key)
{
return _t.Insert(key);
}
private:
RBTree<K, K, SetKeyOfT> _t;
};
}
mymap.h
#include"RBTree.h"
namespace highcool
{
template<class K, class V>
class map
{
struct MapKeyOfT
{
const K& operator()(const pair<K, V>& kv)
{
return kv.first;
}
};
public:
bool insert(const pair<K, V>& kv)
{
return _t.Insert(kv);
}
private:
RBTree<K, pair<K, V>, MapKeyOfT> _t;
};
}
RBTree.h
#pragma once
namespace highcool
{
enum Colour
{
RED,
BLACK
};
template<class T>
struct RBTreeNode
{
// 这里更新控制平衡也要加入parent指针
T _date;
RBTreeNode<T>* _left;
RBTreeNode<T>* _right;
RBTreeNode<T>* _parent;
Colour _col;
RBTreeNode(const T& date)
:_date(date)
, _left(nullptr)
, _right(nullptr)
, _parent(nullptr)
{
}
};
template<class K, class T, class KeyOfT>
class RBTree
{
typedef RBTreeNode<T> Node;
public:
bool Insert(const T& date)
{
if (_root == nullptr)
{
_root = new Node(date);
_root->_col = BLACK;
return true;
}
KeyOfT kot;
Node* parent = nullptr;
Node* cur = _root;
while (cur)
{
if (kot(cur->_date)<kot(date))
{
parent = cur;
cur = cur->_right;
}
else if (kot(cur->_date) > kot(date))
{
parent = cur;
cur = cur->_left;
}
else
{
return false;
}
}
cur = new Node(date);
cur->_col = RED;
if (kot(parent->_date) < kot(date))
{
parent->_right = cur;
}
else
{
parent->_left = cur;
}
// 链接父亲
cur->_parent = parent;
// 父亲是红色,出现连续的红色节点,需要处理
while (parent && parent->_col == RED)
{
Node* grandfather = parent->_parent;
if (parent == grandfather->_left)
{
// g
// p u
Node* uncle = grandfather->_right;
if (uncle && uncle->_col == RED)
{
// 变色
parent->_col = uncle->_col = BLACK;
grandfather->_col = RED;
// 继续往上处理
cur = grandfather;
parent = cur->_parent;
}
else
{
if (cur == parent->_left)
{
// g
// p u
// c
RotateR(grandfather);
parent->_col = BLACK;
grandfather->_col = RED;
}
else
{
// g
// p u
// c
RotateL(parent);
RotateR(grandfather);
cur->_col = BLACK;
grandfather->_col = RED;
}
break;
}
}
else
{
// g
// u p
Node* uncle = grandfather->_left;
// 叔叔存在且为红,-》变色即可
if (uncle && uncle->_col == RED)
{
parent->_col = uncle->_col = BLACK;
grandfather->_col = RED;
// 继续往上处理
cur = grandfather;
parent = cur->_parent;
}
else // 叔叔不存在,或者存在且为黑
{
// 情况二:叔叔不存在或者存在且为黑
// 旋转+变色
// g
// u p
// c
if (cur == parent->_right)
{
RotateL(grandfather);
parent->_col = BLACK;
grandfather->_col = RED;
}
else
{
RotateR(parent);
RotateL(grandfather);
cur->_col = BLACK;
grandfather->_col = RED;
}
break;
}
}
}
_root->_col = BLACK;
return true;
}
void RotateR(Node* parent)
{
Node* subL = parent->_left;
Node* subLR = subL->_right;
parent->_left = subLR;
if (subLR)
subLR->_parent = parent;
Node* pParent = parent->_parent;
subL->_right = parent;
parent->_parent = subL;
if (parent == _root)
{
_root = subL;
subL->_parent = nullptr;
}
else
{
if (pParent->_left == parent)
{
pParent->_left = subL;
}
else
{
pParent->_right = subL;
}
subL->_parent = pParent;
}
}
void RotateL(Node* parent)
{
Node* subR = parent->_right;
Node* subRL = subR->_left;
parent->_right = subRL;
if (subRL)
subRL->_parent = parent;
Node* parentParent = parent->_parent;
subR->_left = parent;
parent->_parent = subR;
if (parentParent == nullptr)
{
_root = subR;
subR->_parent = nullptr;
}
else
{
if (parent == parentParent->_left)
{
parentParent->_left = subR;
}
else
{
parentParent->_right = subR;
}
subR->_parent = parentParent;
}
}
void InOrder()
{
_InOrder(_root);
cout << endl;
}
int Height()
{
return _Height(_root);
}
int Size()
{
return _Size(_root);
}
Node* Find(const K& key)
{
Node* cur = _root;
while (cur)
{
if (cur->_kv.first < key)
{
cur = cur->_right;
}
else if (cur->_kv.first > key)
{
cur = cur->_left;
}
else
{
return cur;
}
}
return nullptr;
}
bool IsBalance()
{
if (_root == nullptr)
return true;
if (_root->_col == RED)
return false;
// 参考值
int refNum = 0;
Node* cur = _root;
while (cur)
{
if (cur->_col == BLACK)
{
++refNum;
}
cur = cur->_left;
}
return Check(_root, 0, refNum);
}
private:
bool Check(Node* root, int blackNum, const int refNum)
{
if (root == nullptr)
{
// 前序遍历走到空时,意味着一条路径走完了
//cout << blackNum << endl;
if (refNum != blackNum)
{
cout << "存在黑色结点的数量不相等的路径" << endl;
return false;
}
return true;
}
// 检查孩子不太方便,因为孩子有两个,且不一定存在,反过来检查父亲就方便多了
if (root->_col == RED && root->_parent->_col == RED)
{
cout << root->_kv.first << "存在连续的红色结点" << endl;
return false;
}
if (root->_col == BLACK)
{
blackNum++;
}
return Check(root->_left, blackNum, refNum)
&& Check(root->_right, blackNum, refNum);
}
void _InOrder(Node* root)
{
if (root == nullptr)
{
return;
}
_InOrder(root->_left);
cout << root->_kv.first << ":" << root->_kv.second << endl;
_InOrder(root->_right);
}
int _Height(Node* root)
{
if (root == nullptr)
return 0;
int leftHeight = _Height(root->_left);
int rightHeight = _Height(root->_right);
return leftHeight > rightHeight ? leftHeight + 1 : rightHeight + 1;
}
int _Size(Node* root)
{
if (root == nullptr)
return 0;
return _Size(root->_left) + _Size(root->_right) + 1;
}
private:
Node* _root = nullptr;
};
}
实现支持iterator
-
iterator实现的大框架跟list的iterator思路是⼀致的,用⼀个类型封装结点的指针,再通过重载运算符,实现让迭代器像指针⼀样访问的行为。
-
begin()会返回中序第⼀个结点的iterator迭代器,因为map和set的迭代器走的是中序遍历,左子树->根结点->右子树
-
这里的难点是operator++和operator–的实现。迭代器++的核心逻辑就是不看全局,只看局部,只考虑当前中序局部要访问的下⼀个结点。
1.迭代器++时,如果it指向的结点的右子树不为空,代表当前结点已经访问完了,要访问下⼀个结点是右子树的中序第⼀个,即右子树的最左结点
2.迭代器++时,如果it指向的结点的右子树空,代表当前结点已经访问完了且当前结点所在的子树也访问完了,要访问的下⼀个结点在当前结点的祖先里面,所以要沿着当前结点到根的祖先路径向上找
(1)如果当前结点是父亲的左,那么下⼀个访问的结点就是当前结点的父亲
(2)如果当前结点是父亲的右,当前当前结点所在的子树访问完了,当前结点所在父亲的子树也访问完了,那么下⼀个访问的需要继续往根的祖先中去找,直到找到孩子是父亲左的那个父亲节点,就是中序要问题的下⼀个结点 -
end()如何表示呢?根没有父亲,没有找到孩子是父亲左的那个祖先,已经遍历到根了,父亲为空,那我们就把it中的结点指针置为nullptr,我们用nullptr去充当end。
-
注意–end()判断到结点时空,需要特殊处理⼀下,让迭代器结点指向最右结点。
-
迭代器–的实现跟++的思路完全类似,逻辑正好反过来即可,不赘述了。
-
还有一些细节要点,set的iterator不支持修改,我们把set的第二个模板参数改成const K即可,RBTree <K,const K, SetKeyOfT> _t;map的iterator不支持修改key但是可以修改value,我们把map的第二个模板参数pair的第⼀个参数改成const K即可, RBTree<K, pair<const K, V>, MapKeyOfT> _t。
实现map支持[]
map要支持[]主要需要修改insert返回值支持,修改RBtree中的insert返回值为
pair<Iterator, bool> Insert(const T& data)
highcool::map和highcool::set代码实现
- myset.h
#pragma once
#include"RBTree.h"
namespace highcool
{
template<class K>
class set
{
struct SetKeyOfT
{
const K& operator()(const K& key)
{
return key;
}
};
public:
typedef typename RBTree<K,const K,SetKeyOfT>::Iterator iterator;
typedef typename RBTree<K, const K, SetKeyOfT>::ConstIterator const_iterator;
iterator begin()
{
return _t.Begin();
}
iterator end()
{
return _t.End();
}
const_iterator begin() const
{
return _t.Begin();
}
const_iterator end() const
{
return _t.End();
}
pair<iterator,bool> insert(const K& key)
{
return _t.Insert(key);
}
iterator find(const K& key)
{
return _t.Find(key);
}
private:
RBTree<K, const K, SetKeyOfT> _t;
};
}
- mymap.h
#pragma once
#include"RBTree.h"
namespace highcool
{
template<class K, class V>
class map
{
struct MapKeyOfT
{
const K& operator()(const pair<K, V>& kv)
{
return kv.first;
}
};
public:
typedef typename RBTree<K, pair<const K, V>, MapKeyOfT>::Iterator iterator;
typedef typename RBTree<K, pair<const K, V>, MapKeyOfT>::ConstIterator const_iterator;
iterator begin()
{
return _t.Begin();
}
iterator end()
{
return _t.End();
}
const_iterator begin() const
{
return _t.Begin();
}
const_iterator end() const
{
return _t.End();
}
pair<iterator, bool> insert(const pair<K, V>& kv)
{
return _t.Insert(kv);
}
iterator find(const K& key)
{
return _t.Find(key);
}
V& operator[](const K& key)
{
pair<iterator, bool> ret = insert({ key,V() });
return ret.first->second;
}
private:
RBTree<K, pair<const K, V>, MapKeyOfT> _t;
};
}
- RBTree.h
#pragma once
namespace highcool
{
enum Colour
{
RED,
BLACK
};
template<class T>
struct RBTreeNode
{
// 这里更新控制平衡也要加入parent指针
T _date;
RBTreeNode<T>* _left;
RBTreeNode<T>* _right;
RBTreeNode<T>* _parent;
Colour _col;
RBTreeNode(const T& date)
:_date(date)
, _left(nullptr)
, _right(nullptr)
, _parent(nullptr)
{
}
};
template<class T,class Ref,class Ptr>
struct RBTreeIterator
{
typedef RBTreeNode<T> Node;
typedef RBTreeIterator<T, Ref, Ptr> Self;
Node* _node;
Node* _root;
RBTreeIterator(Node* node,Node* root)
:_node(node)
,_root(root)
{ }
Self operator++()
{
if (_node->_right)
{
Node* cur = _node->_right;
while (cur->_left)
{
cur = cur->_left;
}
_node = cur;
}
else
{
Node* cur = _node;
Node* parent = cur->_parent;
while (parent&&cur == parent->_right)
{
cur = parent;
parent = cur->_parent;
}
_node = parent;
}
return *this;
}
Self& operator--()
{
if (_node == nullptr)
{
Node* cur = _root;
while (cur && cur->_right)
{
cur = cur->_right;
}
_node = cur;
}
else if (_node->_left)
{
Node* cur = _node->_left;
while (cur->_right)
{
cur = cur->_right;
}
_node = cur;
}
else
{
Node* cur = _node;
Node* parent = cur->_parent;
while (parent && cur == parent->_left)
{
cur = parent;
parent = cur->_parent;
}
_node = parent;
}
return *this;
}
Ref operator*()
{
return _node->_date;
}
Ptr operator->()
{
return &(_node->_date);
}
bool operator==(const Self& s) const
{
return _node == s._node;
}
bool operator!=(const Self& s) const
{
return _node != s._node;
}
};
template<class K, class T, class KeyOfT>
class RBTree
{
typedef RBTreeNode<T> Node;
public:
typedef RBTreeIterator<T, T&, T*> Iterator;
typedef RBTreeIterator<T, const T&, const T*> ConstIterator;
Iterator Begin()
{
Node* cur = _root;
while (cur && cur->_left)
{
cur = cur->_left;
}
return Iterator(cur, _root);
}
Iterator End()
{
return Iterator(nullptr, _root);
}
ConstIterator Begin() const
{
Node* cur = _root;
while (cur && cur->_left)
{
cur = cur->_left;
}
return ConstIterator(cur, _root);
}
ConstIterator End() const
{
return ConstIterator(nullptr, _root);
}
RBTree() = default;
~RBTree()
{
Destroy(_root);
_root = nullptr;
}
void Destroy(Node* root)
{
if (root == nullptr)
return;
Destroy(root->_left);
Destroy(root->_right);
delete root;
}
pair<Iterator,bool> Insert(const T& date)
{
if (_root == nullptr)
{
_root = new Node(date);
_root->_col = BLACK;
return {Iterator(_root,_root),true};
}
KeyOfT kot;
Node* parent = nullptr;
Node* cur = _root;
while (cur)
{
if (kot(cur->_date)<kot(date))
{
parent = cur;
cur = cur->_right;
}
else if (kot(cur->_date) > kot(date))
{
parent = cur;
cur = cur->_left;
}
else
{
return { Iterator(cur,_root),false };
}
}
cur = new Node(date);
Node* newnode = cur;
cur->_col = RED;
if (kot(parent->_date) < kot(date))
{
parent->_right = cur;
}
else
{
parent->_left = cur;
}
// 链接父亲
cur->_parent = parent;
// 父亲是红色,出现连续的红色节点,需要处理
while (parent && parent->_col == RED)
{
Node* grandfather = parent->_parent;
if (parent == grandfather->_left)
{
// g
// p u
Node* uncle = grandfather->_right;
if (uncle && uncle->_col == RED)
{
// 变色
parent->_col = uncle->_col = BLACK;
grandfather->_col = RED;
// 继续往上处理
cur = grandfather;
parent = cur->_parent;
}
else
{
if (cur == parent->_left)
{
// g
// p u
// c
RotateR(grandfather);
parent->_col = BLACK;
grandfather->_col = RED;
}
else
{
// g
// p u
// c
RotateL(parent);
RotateR(grandfather);
cur->_col = BLACK;
grandfather->_col = RED;
}
break;
}
}
else
{
// g
// u p
Node* uncle = grandfather->_left;
// 叔叔存在且为红,-》变色即可
if (uncle && uncle->_col == RED)
{
parent->_col = uncle->_col = BLACK;
grandfather->_col = RED;
// 继续往上处理
cur = grandfather;
parent = cur->_parent;
}
else // 叔叔不存在,或者存在且为黑
{
// 情况二:叔叔不存在或者存在且为黑
// 旋转+变色
// g
// u p
// c
if (cur == parent->_right)
{
RotateL(grandfather);
parent->_col = BLACK;
grandfather->_col = RED;
}
else
{
RotateR(parent);
RotateL(grandfather);
cur->_col = BLACK;
grandfather->_col = RED;
}
break;
}
}
}
_root->_col = BLACK;
return { Iterator(newnode,_root),true };
}
void RotateR(Node* parent)
{
Node* subL = parent->_left;
Node* subLR = subL->_right;
parent->_left = subLR;
if (subLR)
subLR->_parent = parent;
Node* pParent = parent->_parent;
subL->_right = parent;
parent->_parent = subL;
if (parent == _root)
{
_root = subL;
subL->_parent = nullptr;
}
else
{
if (pParent->_left == parent)
{
pParent->_left = subL;
}
else
{
pParent->_right = subL;
}
subL->_parent = pParent;
}
}
void RotateL(Node* parent)
{
Node* subR = parent->_right;
Node* subRL = subR->_left;
parent->_right = subRL;
if (subRL)
subRL->_parent = parent;
Node* parentParent = parent->_parent;
subR->_left = parent;
parent->_parent = subR;
if (parentParent == nullptr)
{
_root = subR;
subR->_parent = nullptr;
}
else
{
if (parent == parentParent->_left)
{
parentParent->_left = subR;
}
else
{
parentParent->_right = subR;
}
subR->_parent = parentParent;
}
}
void InOrder()
{
_InOrder(_root);
cout << endl;
}
int Height()
{
return _Height(_root);
}
int Size()
{
return _Size(_root);
}
Iterator Find(const K& key)
{
Node* cur = _root;
while (cur)
{
if (cur->_kv.first < key)
{
cur = cur->_right;
}
else if (cur->_kv.first > key)
{
cur = cur->_left;
}
else
{
return Iterator(cur,_root);
}
}
return End();
}
bool IsBalance()
{
if (_root == nullptr)
return true;
if (_root->_col == RED)
return false;
// 参考值
int refNum = 0;
Node* cur = _root;
while (cur)
{
if (cur->_col == BLACK)
{
++refNum;
}
cur = cur->_left;
}
return Check(_root, 0, refNum);
}
private:
bool Check(Node* root, int blackNum, const int refNum)
{
if (root == nullptr)
{
// 前序遍历走到空时,意味着一条路径走完了
//cout << blackNum << endl;
if (refNum != blackNum)
{
cout << "存在黑色结点的数量不相等的路径" << endl;
return false;
}
return true;
}
// 检查孩子不太方便,因为孩子有两个,且不一定存在,反过来检查父亲就方便多了
if (root->_col == RED && root->_parent->_col == RED)
{
cout << root->_kv.first << "存在连续的红色结点" << endl;
return false;
}
if (root->_col == BLACK)
{
blackNum++;
}
return Check(root->_left, blackNum, refNum)
&& Check(root->_right, blackNum, refNum);
}
void _InOrder(Node* root)
{
if (root == nullptr)
{
return;
}
_InOrder(root->_left);
cout << root->_kv.first << ":" << root->_kv.second << endl;
_InOrder(root->_right);
}
int _Height(Node* root)
{
if (root == nullptr)
return 0;
int leftHeight = _Height(root->_left);
int rightHeight = _Height(root->_right);
return leftHeight > rightHeight ? leftHeight + 1 : rightHeight + 1;
}
int _Size(Node* root)
{
if (root == nullptr)
return 0;
return _Size(root->_left) + _Size(root->_right) + 1;
}
private:
Node* _root = nullptr;
};
}
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