#方法一（数字解包,最快！）x = 1234a,b,c,d = map(int,str(x))print(tuple({a,b,c,d}))#方法二（字符串转换函数,也快,注意缩进tab和空格统一）def position(number):ls=[]for i in str(number):ls.append(int(i))return print(tuple(ls))position(1234)