需求: vue项目中,点击左侧菜单,tags页显示当前打开的菜单,并且高亮显示当前菜单

实现效果:

实现代码:在vuex里面定义tags存放所有打开的菜单,和当前打开的索引curtagsIndex:,通过遍历tags,看是否等于当前索引

1.在store的index.js文件里面定义tags和curtagsIndex

const store = new Vuex.Store({
    modules: {
    tags:[],
    curTagsIndex:"-1",
    },
  mutations: {
    SET_CURTAGS: (state, index) => {
      state.curTagsIndex = index
    },
  }
})  

 

  <div class="tag_list" v-for="(tag,index)  in  tags" @click="jump(tag)" :class="{ active:curTagsIndex == index}">
        <span>{{tag.name}}</span>
        <i class="el-icon-close" @click="close(tag)"></i>
      </div>



<script>
  import { mapState, mapGetters,mapMutations } from "vuex";
    export default{   
      computed: {
        ...mapGetters(["tags","curTagsIndex"]),
      },
      methods:{
        ...mapMutations(["SET_CURTAGS"]),
        jump(val){
          this.$router.push(val.path);
          this.tags.forEach((item,index)=>{
             if(item.name==val.name){
               this.$store.commit("SET_CURTAGS",index);
            }
          })

        },
      

      },
        
    }
</script>
<style lang="less" scoped>
 
  .active{
     background:#f1f4f5;

  }

</style>

 

转载于:https://www.cnblogs.com/xieli26/p/9947231.html

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