如果你要在脚本里动态的调用方法，而且可能的入口条件还会依据用户的输入值影响到。如何解决呢。

1、事件发起

 <el-button icon="el-icon-video-play" type="text" @click="run">
          运行
        </el-button>
        <el-button icon="el-icon-view" type="text" @click="showJson">
          查看json
        </el-button>
        <el-button icon="el-icon-download" type="text" @click="download">
          导出文件
        </el-button>
        <el-button class="copy-btn-main" icon="el-icon-document-copy" type="text" @click="copy">
          复制
        </el-button>
        <el-button class="delete-btn" icon="el-icon-delete" type="text" @click="empty">
          清空
 </el-button>

2、对应的方法

showJson() {
      this.AssembleFormData()
      this.jsonDrawerVisible = true
    },
    download() {
      this.dialogVisible = true
      this.showFileName = true
      this.operationType = 'download'
    },
    run() {
      this.dialogVisible = true
      this.showFileName = false
      this.operationType = 'run'
    },
    copy() {
      this.dialogVisible = true
      this.showFileName = false
      this.operationType = 'copy'
    },

3、公共执行方法

 generate(data) {
      //设置要执行的方法execRun(data)
      const func = this[`exec${titleCase(this.operationType)}`]
      this.generateConf = data
//运行方法
      func && func(data)
    },
   

4、各自的方法

 execRun(data) {
      this.AssembleFormData()
     
      this.drawerVisible = true
    },
    execDownload(data) {
      const codeStr = this.generateCode()
      const blob = new Blob([codeStr], { type: 'text/plain;charset=utf-8' })
      saveAs(blob, data.fileName)
    },
    execCopy(data) {
      document.getElementById('copyNode').click()
    },
    empty() {
      this.$confirm('确定要清空所有组件吗？', '提示', { type: 'warning' }).then(
        () => {
          this.drawingList = []
          this.idGlobal = 100
        }
      )
    },