# 写一个函数,统计字符串中有几个字母,几个数字,几个空格,几个其他字符,并返回结果。
import redef statistical(s):letter = "[a-zA-Z]"digital = "[0-9]"blank = "[ ]"letter_numbers = 0digital_numbers = 0blank_numbers = 0for i in s:if(re.match(letter,i)) != None:lett...
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import re
def statistical(s):
letter = "[a-zA-Z]"
digital = "[0-9]"
blank = "[ ]"
letter_numbers = 0
digital_numbers = 0
blank_numbers = 0
for i in s:
if(re.match(letter,i)) != None:
letter_numbers += 1
if(re.match(digital,i)) != None:
digital_numbers += 1
if(re.match(blank,i)) != None:
blank_numbers += 1
others = len(s) - letter_numbers - digital_numbers - blank_numbers
return letter_numbers,digital_numbers,blank_numbers,others
if __name__ == "__main__":
s = "abc 123 ABC =-"
print("字母的数量:"+str(statistical(s)[0]))
print("数字的数量:" + str(statistical(s)[1]))
print("空格的数量:" + str(statistical(s)[2]))
print("其他的数量:" + str(statistical(s)[3]))
输出结果:
字母的数量:6
数字的数量:3
空格的数量:3
其他的数量:2
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