A*算法的精髓：f(n)=g(n)+h(n)f(n)=g(n)+h(n)f(n)=g(n)+h(n)h(n)h(n)h(n)是当前状态nnn到目标状态的欧几里得距离和。利用堆优化BFSBFSBFS即可。还可以在BFSBFSBFS时记录前驱，然后倒着找到路线方案。/** @author:codancer* @createTime:2020-11-28, 17:31:10*/#include <

A. One-dimensional Japanese Crosswordtime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputRecently Adaltik discovered japanese crosswords. Japanese cros