#include<stdio.h>void main(){float x[5],s;float avg;int i,n,count=0;s=0;printf("请输入人数:");scanf("%d",&n);for(i=0;i<n;i++){printf("请输入第%d个学生的成绩:",i+1);scanf("%f",&x[i]);s=s+x[i];if(x[i]

方法一：常规计算#include <stdio.h>void main(){char a[32],b[32],*p1=a,*p2=b;int ret;printf("请输入第一个字符串：\n");gets(a);printf("请输入第二个字符串：\n");gets(b);while(*p1&&*p1==*p2){p1++;p2++;}ret=*p1-*p2;print

#include<stdio.h>#include<string.h>void main(){int i,count=0;char s[32];printf("请输入一个字符串：");gets(s);for(i=0;i<strlen(s);i++){if(s[i]>='0'&&s[i]<='9'){count++;}}printf("数字字

【代码】C语言 用递归方法计算n阶勒让德多项式的值。

#include <stdio.h>void main(){int i,j;double m=0,s=0;for(i=1;i<=9;i++){for(j=1;j<=i;j++){m=m*10+i;s+=m;}}printf("%g",s); // 1.35926e+044}

#include<stdio.h>int main(){double x=2,y=1,sum=0,t;int i,n;printf("请输入求和项数：");scanf("%d",&n);for(i=1;i<=n;i++){sum+=x/y;t=x;x=y+x;y=t;}printf("2/1,3/2,5/3,8/5,13/8,21/13……前%d项和为：%

#include<stdio.h>void fun(float *sn,int n){float s=0,flag=-1.0;int i;for(i=0;i<n;i++){flag=-1*flag;s+=flag/(2*i+1);}*sn=s;printf("前%d项结果为：%f",n,*sn);}void main(){float sn;int n;printf("请输入项数：

#include <stdio.h>void fun(int n){int i,flag=1;float sn=0;for(i=1;i<=n;i++){sn+=1.0/i*flag;flag=-flag;}printf("前%d项结果为：%f",n,sn);}void main(){int i,n;printf("请输入项数：");scanf("%d",&n);fun(n

方法一：常规计算#include <stdio.h>void main(){char a[32],b[32],*p1=a,*p2=b;int ret;printf("请输入第一个字符串：\n");gets(a);printf("请输入第二个字符串：\n");gets(b);while(*p1&&*p1==*p2){p1++;p2++;}ret=*p1-*p2;print

精确要求：当通项的绝对值小于10^-6时为止。公式如下：#include <stdio.h>#include <math.h>double mycos(double x){int n=1;double s=0,t=1.0;while(fabs(t)>=1e-6){s+=t;t*=(-1)*x*x/(n*(n+1));n=n+2;}return s;}void main