vue根据百度api获取到自己所在位置的经纬度以及具体的位置名称

<group class="site" label-width="5.5em" label-margin-right="1em" label-align="right">
            <x-textarea title="当前位置" v-model="Burst.address" placeholder="选择当前位置"></x-textarea>
            <x-button type="primary">
              <img @click="getShopWxConfig" src="/static/images/inner/site.png" alt>
            </x-button>
          </group>

//获取地址和经纬度
    getShopWxConfig() {
      let $this = this;
      wx.checkJsApi({
        jsApiList: ["getLocation"],
        success: function(res) {
          if (res.checkResult.getLocation == false) {
            alert(
              "你的微信版本太低，不支持微信JS接口，请升级到最新的微信版本！"
            );
            return;
          }
        }
      });
      wx.getLocation({
        type: "wgs84",
        success: function(res) {
          //转换为bd02
          var convertor = new BMap.Convertor();
          var pointArr = [];
          var ggPoint = new BMap.Point(res.longitude, res.latitude);
          pointArr.push(ggPoint);
          convertor.translate(pointArr, 1, 5, $this.translateCallback);
        },
        cancel: function(res) {
          alert("用户拒绝授权获取地理位置");
        }
      });
    },
    translateCallback(data){//坐标转换完之后的回调函数
      let $this = this;
      if(data.status === 0) {
        $this.Burst.longitude = data.points[0].lng;
        $this.Burst.latitude = data.points[0].lat;
        let address = ""
        //通过baiduMap API获取街道名称
        let point = new BMap.Point(data.points[0].lng, data.points[0].lat);
        let gc = new BMap.Geocoder();
        gc.getLocation(point, function(rs) {
          let addComp = rs.addressComponents;
          address =
            addComp.city +
            addComp.district +
            addComp.street +
            addComp.streetNumber;
          $this.Burst.address = address;
          $this.scrollFn();
        });
      }
    },

后端百度api经纬度BD09=>WGS84=>GCJ-02之前的互相转换的utils类

/**
 * Created by CaiHB on 2015/11/2 15:31.
 * E-mail:caihaobing@sina.cn
 */
public class CoordinateConvert {

    /**
     * 坐标转换程序
     * <p/>
     * WGS84坐标系：即地球坐标系，国际上通用的坐标系。Earth
     * <p/>
     * GCJ02坐标系：即火星坐标系，WGS84坐标系经加密后的坐标系。Mars
     * <p/>
     * BD09坐标系：即百度坐标系，GCJ02坐标系经加密后的坐标系。  Bd09
     * <p/>
     * 搜狗坐标系、图吧坐标系等，估计也是在GCJ02基础上加密而成的。
     * <p/>
     * 百度地图API        百度坐标
     * 腾讯搜搜地图API 火星坐标
     * 搜狐搜狗地图API 搜狗坐标*
     * 阿里云地图API     火星坐标
     * 图吧MapBar地图API 图吧坐标
     * 高德MapABC地图API 火星坐标
     * 灵图51ditu地图API 火星坐标
     */
    private static double PI = Math.PI;
    private static double AXIS = 6378245.0;  //
    private static double OFFSET = 0.00669342162296594323;  //(a^2 - b^2) / a^2
    private static double X_PI = PI * 3000.0 / 180.0;

    //GCJ-02=>BD09 火星坐标系=>百度坐标系
    public static double[] gcj2BD09(double glat, double glon) {
        double x = glon;
        double y = glat;
        double[] latlon = new double[2];
        double z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * X_PI);
        double theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * X_PI);
        latlon[0] = z * Math.sin(theta) + 0.006;
        latlon[1] = z * Math.cos(theta) + 0.0065;
        return latlon;
    }

    //BD09=>GCJ-02 百度坐标系=>火星坐标系
    public static double[] bd092GCJ(double glat, double glon) {
        double x = glon - 0.0065;
        double y = glat - 0.006;
        double[] latlon = new double[2];
        double z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * X_PI);
        double theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * X_PI);
        latlon[0] = z * Math.sin(theta);
        latlon[1] = z * Math.cos(theta);
        return latlon;
    }

    //BD09=>WGS84 百度坐标系=>地球坐标系
    public static double[] bd092WGS(double glat, double glon) {
        double[] latlon = bd092GCJ(glat, glon);
        return gcj2WGS(latlon[0], latlon[1]);
    }

    // WGS84=》BD09   地球坐标系=>百度坐标系
    public static double[] wgs2BD09(double wgLat, double wgLon) {
        double[] latlon = wgs2GCJ(wgLat, wgLon);
        return gcj2BD09(latlon[0], latlon[1]);
    }

    // WGS84=》GCJ02   地球坐标系=>火星坐标系
    public static double[] wgs2GCJ(double wgLat, double wgLon) {
        double[] latlon = new double[2];
        if (outOfChina(wgLat, wgLon)) {
            latlon[0] = wgLat;
            latlon[1] = wgLon;
            return latlon;
        }
        double[] deltaD = delta(wgLat, wgLon);
        latlon[0] = wgLat + deltaD[0];
        latlon[1] = wgLon + deltaD[1];
        return latlon;
    }

    //GCJ02=>WGS84   火星坐标系=>地球坐标系(粗略)
    public static double[] gcj2WGS(double glat, double glon) {
        double[] latlon = new double[2];
        if (outOfChina(glat, glon)) {
            latlon[0] = glat;
            latlon[1] = glon;
            return latlon;
        }
        double[] deltaD = delta(glat, glon);
        latlon[0] = glat - deltaD[0];
        latlon[1] = glon - deltaD[1];
        return latlon;
    }

    //GCJ02=>WGS84   火星坐标系=>地球坐标系（精确）
    public static double[] gcj2WGSExactly(double gcjLat, double gcjLon) {
        double initDelta = 0.01;
        double threshold = 0.000000001;
        double dLat = initDelta, dLon = initDelta;
        double mLat = gcjLat - dLat, mLon = gcjLon - dLon;
        double pLat = gcjLat + dLat, pLon = gcjLon + dLon;
        double wgsLat, wgsLon, i = 0;
        while (true) {
            wgsLat = (mLat + pLat) / 2;
            wgsLon = (mLon + pLon) / 2;
            double[] tmp = wgs2GCJ(wgsLat, wgsLon);
            dLat = tmp[0] - gcjLat;
            dLon = tmp[1] - gcjLon;
            if ((Math.abs(dLat) < threshold) && (Math.abs(dLon) < threshold))
                break;

            if (dLat > 0) pLat = wgsLat;
            else mLat = wgsLat;
            if (dLon > 0) pLon = wgsLon;
            else mLon = wgsLon;

            if (++i > 10000) break;
        }
        double[] latlon = new double[2];
        latlon[0] = wgsLat;
        latlon[1] = wgsLon;
        return latlon;
    }

    //两点距离
    public static double distance(double latA, double logA, double latB, double logB) {
        int earthR = 6371000;
        double x = Math.cos(latA * Math.PI / 180) * Math.cos(latB * Math.PI / 180) * Math.cos((logA - logB) * Math.PI / 180);
        double y = Math.sin(latA * Math.PI / 180) * Math.sin(latB * Math.PI / 180);
        double s = x + y;
        if (s > 1)
            s = 1;
        if (s < -1)
            s = -1;
        double alpha = Math.acos(s);
        double distance = alpha * earthR;
        return distance;
    }

    public static double[] delta(double wgLat, double wgLon) {
        double[] latlng = new double[2];
        double dLat = transformLat(wgLon - 105.0, wgLat - 35.0);
        double dLon = transformLon(wgLon - 105.0, wgLat - 35.0);
        double radLat = wgLat / 180.0 * PI;
        double magic = Math.sin(radLat);
        magic = 1 - OFFSET * magic * magic;
        double sqrtMagic = Math.sqrt(magic);
        dLat = (dLat * 180.0) / ((AXIS * (1 - OFFSET)) / (magic * sqrtMagic) * PI);
        dLon = (dLon * 180.0) / (AXIS / sqrtMagic * Math.cos(radLat) * PI);
        latlng[0] = dLat;
        latlng[1] = dLon;
        return latlng;
    }

    public static boolean outOfChina(double lat, double lon) {
        if (lon < 72.004 || lon > 137.8347)
            return true;
        if (lat < 0.8293 || lat > 55.8271)
            return true;
        return false;
    }

    public static double transformLat(double x, double y) {
        double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.sqrt(Math.abs(x));
        ret += (20.0 * Math.sin(6.0 * x * PI) + 20.0 * Math.sin(2.0 * x * PI)) * 2.0 / 3.0;
        ret += (20.0 * Math.sin(y * PI) + 40.0 * Math.sin(y / 3.0 * PI)) * 2.0 / 3.0;
        ret += (160.0 * Math.sin(y / 12.0 * PI) + 320 * Math.sin(y * PI / 30.0)) * 2.0 / 3.0;
        return ret;
    }

    public static double transformLon(double x, double y) {
        double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.sqrt(Math.abs(x));
        ret += (20.0 * Math.sin(6.0 * x * PI) + 20.0 * Math.sin(2.0 * x * PI)) * 2.0 / 3.0;
        ret += (20.0 * Math.sin(x * PI) + 40.0 * Math.sin(x / 3.0 * PI)) * 2.0 / 3.0;
        ret += (150.0 * Math.sin(x / 12.0 * PI) + 300.0 * Math.sin(x / 30.0 * PI)) * 2.0 / 3.0;
        return ret;
    }

}

原文作者技术博客：https://www.jianshu.com/u/ac4daaeecdfe
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