vue+element 身份证号码以及有效性校验 适用 15位 或18位
data () {let idCardValidity = (rule, code, callback) => {var city = { 11: "北京", 12: "天津", 13: "河北", 14: "山西", 15: "内蒙古", 21: "辽宁", 22: "吉林", 23: "黑龙江 ", 31: "上海", 32: "江苏", 33: "浙江",...
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data () {
let idCardValidity = (rule, code, callback) => {
var city = { 11: "北京", 12: "天津", 13: "河北", 14: "山西", 15: "内蒙古", 21: "辽宁", 22: "吉林", 23: "黑龙江 ", 31: "上海", 32: "江苏", 33: "浙江", 34: "安徽", 35: "福建", 36: "江西", 37: "山东", 41: "河南", 42: "湖北 ", 43: "湖南", 44: "广东", 45: "广西", 46: "海南", 50: "重庆", 51: "四川", 52: "贵州", 53: "云南", 54: "西藏 ", 61: "陕西", 62: "甘肃", 63: "青海", 64: "宁夏", 65: "新疆", 71: "台湾", 81: "香港", 82: "澳门", 91: "国外 " };
var tip = ""
var pass = true
if (!code || !/^\d{6}(18|19|20)?\d{2}(0[1-9]|1[012])(0[1-9]|[12]\d|3[01])\d{3}(\d|X)$/i.test(code)) {
tip = "身份证号格式错误"
pass = false;
} else if (!city[code.substr(0, 2)]) {
tip = "地址编码错误"
pass = false
} else {
// 18位身份证需要验证最后一位校验位
if (code.length === 18) {
code = code.split('')
// ∑(ai×Wi)(mod 11)
// 加权因子
var factor = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2]
// 校验位
var parity = [1, 0, 'X', 9, 8, 7, 6, 5, 4, 3, 2]
var sum = 0
var ai = 0
var wi = 0
for (var i = 0; i < 17; i++) {
ai = code[i]
wi = factor[i]
sum += ai * wi
}
var last = parity[sum % 11];
if (parity[sum % 11] != code[17]) {
tip = "校验位错误"
pass = false
}
}
}
if (!pass) {
callback(new Error(tip))
} else {
callback()
}
// if (!pass) alert(tip)
// return pass
}
return {
personInfo: {
idCard: "",
},
rules: {
idCard: [{ required: true, message: '请输入证件号', trigger: 'blur' },
{
pattern: /(^\d{8}(0\d|10|11|12)([0-2]\d|30|31)\d{3}$)|(^\d{6}(18|19|20)\d{2}(0\d|10|11|12)([0-2]\d|30|31)\d{3}(\d|X|x)$)/,
message: '请输入正确的证件号'
},
{ validator: idCardValidity, trigger: 'blur' }],
}
}
},
1.规则方法写在 data里 return之前。
2. 身份证有效性校验规则来源与百度
校验公示:∑(ai×Wi)(mod 11)
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