功能需求：点击底部导航栏切换图片及页面（如下效果）

（以下代码只展示重要部分，css等样式请自行编写）

父组件代码（导航栏页）

<template>
  <div>
    <keep-alive>
      <router-view></router-view>
    </keep-alive>
    <!--      底部导航栏-->
    <el-row class="bottom-nav">
      <router-link
        v-for="(i,index) in list"
        :key="index"
        @click="addClassName(i.path)"
        :to="i.path">
        <el-col :span="8">
<!--          三元表达式-->
          <div><img :src="i.path===$route.path?list[index].active : list[index].img"></div>
          <div class="grid-content">{{i.name}}</div>
        </el-col>
      </router-link>
    </el-row>
  </div>
</template>

<script>
    export default {
        name: "homePage",
        props:['tabName'],
        data() {
            return {
                num:true,
               list:[

                   {
                       img: require("../../assets/image/homePage-1.png"),  //原始显示的图标
                       active: require("../../assets/image/homePage.png"), //点击之后要显示的图标
                       name: "首页",
                       path: "/homePage"
                   },
                   {
                       img: require("../../assets/image/news-1.png"),
                       active: require("../../assets/image/news.png"),
                       name: "消息",
                       path: "/news"
                   },
                   {
                       img: require("../../assets/image/myself-1.png"),
                       active: require("../../assets/image/myself.png"),
                       name: "我的",
                       path: "/myself"
                   }

               ],


            }
        },

        methods: {
            addClassName: function(path) {
                this.$router.replace(path);
            },
        }
    }
</script>

注意：图片必须要用require

子组件部分

路由配置router.js

若要看二级路由切换父组件样式保留请看https://blog.csdn.net/qq_41589917/article/details/103894228
若有其他疑惑请在下方留言