Catch That Cow
DescriptionFarmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point
·
#include<cstdio>
#include<iostream>
#include<algorithm>
#include<stdio.h>
#include<queue>
using namespace std;
int n;
typedef pair<int,int> tp;
queue <tp> pp;
int sn[200010]= {0};
int bfs(int m,int s)
{
if(m>=n)
return m-n;
pp.push(tp(m,s));
while(pp.size())
{
if(m<0) continue;
tp p=pp.front();
pp.pop();
if(sn[p.first]==0)
{
sn[p.first] =1;
if(p.first==n) return p.second;
if(p.first+1<=1+n)
pp.push(tp(p.first+1,p.second+1));
if(p.first-1<=1+n)
pp.push(tp(p.first-1,p.second+1));
if(p.first*2<=1+n&&p.first!=0)
pp.push(tp(p.first*2,p.second+1));
}
}
return 0;
}
int main()
{
int m;
scanf("%d%d",&m,&n);
printf("%d",bfs(m,0));
return 0;
}
更多推荐
已为社区贡献1条内容
所有评论(0)