linux 内核源码分析 - 获取数组的大小
#define ARRAY_SIZE(x) (sizeof(x) / sizeof((x)[0])) 测试程序：#include#includestruct dev{int a;char b;float c;};struct dev devs[]={{1,'a',7.0,},{1,'a',7.0,},{
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#define ARRAY_SIZE(x) (sizeof(x) / sizeof((x)[0]))
测试程序：
#include<stdio.h>
#include<stdlib.h>
struct dev
{
int a;
char b;
float c;
};
struct dev devs[]=
{
{
1,'a',7.0,
},
{
1,'a',7.0,
},
{
1,'a',7.0,
},
};
int main()
{
printf("int is %d \n" ,sizeof(int));
printf("char is %d\n",sizeof(char));
printf("float is %d\n",sizeof(float));
printf("devs is %d \n",sizeof(devs));
printf("devs[0] is %d\n",sizeof(devs[0]));
printf("num is %d \n",sizeof(devs)/sizeof(devs[0]));
return 0;
}
实践结果如下：
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