如何解析存储在Java字符串对象中的XML？

Java的XMLRe读器只能解析URI或输入流中的XML文档。是否无法从包含XML数据的字符串进行分析？

现在我有以下内容：

try {

SAXParserFactory factory = SAXParserFactory.newInstance();

SAXParser sp = factory.newSAXParser();

XMLReader xr = sp.getXMLReader();

ContactListXmlHandler handler = new ContactListXmlHandler();

xr.setContentHandler(handler);

xr.p

} catch (ParserConfigurationException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (SAXException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

在我的处理程序上，我有：

public class ContactListXmlHandler extends DefaultHandler implements Resources {

private List contactNameList = new ArrayList();

private ContactName contactItem;

private StringBuffer sb;

public List getContactNameList() {

return contactNameList;

}

@Override

public void startDocument() throws SAXException {

// TODO Auto-generated method stub

super.startDocument();

sb = new StringBuffer();

}

@Override

public void startElement(String uri, String localName, String qName,

Attributes attributes) throws SAXException {

// TODO Auto-generated method stub

super.startElement(uri, localName, qName, attributes);

if(localName.equals(XML_CONTACT_NAME)){

contactItem = new ContactName();

}

sb.setLength(0);

}

@Override

public void characters(char[] ch, int start, int length){

// TODO Auto-generated method stub

try {

super.characters(ch, start, length);

} catch (SAXException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

sb.append(ch, start, length);

}

@Override

public void endDocument() throws SAXException {

// TODO Auto-generated method stub

super.endDocument();

}

/**

* where the real stuff happens

*/

@Override

public void endElement(String uri, String localName, String qName)

throws SAXException {

// TODO Auto-generated method stub

//super.endElement(arg0, arg1, arg2);

if(contactItem != null){

if (localName.equalsIgnoreCase("title")) {

contactItem.setUid(sb.toString());

Log.d("handler","setTitle =" + sb.toString());

} else if (localName.equalsIgnoreCase("link")) {

contactItem.setFullName(sb.toString());

} else if (localName.equalsIgnoreCase("item")){

Log.d("handler","adding rss item");

contactNameList.add(contactItem);

}

sb.setLength(0);

}

}

提前谢谢

您可以看到：stackoverflow.com/questions/247161/&hellip；

SAXParser可以读取输入源。

输入源可以在其构造函数中获取读取器

因此，可以通过StringReader放置解析XML字符串

new InputSource(new StringReader("... your xml here....")));

干杯。似乎奏效了。

使用一行代码尝试jcabi xml(请参阅本文)：

XML xml = new XMLDocument("...")

您的XML可能足够简单，可以使用DOM或SAX API手动解析，但我仍然建议使用XML序列化API(如JAXB、XStream)或Simple，因为编写自己的XML序列化/反序列化代码很麻烦。

请注意，XStream FAQ错误地声称必须将生成的类与JAXB一起使用：

How does XStream compare to JAXB (Java API for XML Binding)?

JAXB is a Java binding tool. It generates Java code from a schema and

you are able to transform from those classes into XML matching the

processed schema and back. Note, that you cannot use your own objects,

you have to use what is generated.

看起来这是真的，但JAXB 2不再要求您使用从模式生成的Java类。

如果您走这条路线，请务必查看我提到的序列化/编组API的并行比较：

http://blog.bdougan.com/2010/10/how-do-jaxb-compare-to-xstream.htmlhttp://blog.bdougan.com/2010/10/how-do-jaxb-compare-to-simple.html

看看这个：http://www.rgagnon.com/javadetails/java-0573.html

import javax.xml.parsers.*;

import org.xml.sax.InputSource;

import org.w3c.dom.*;

import java.io.*;

public class ParseXMLString {

public static void main(String arg[]) {

String xmlRecords =

"" +

"" +

"   John" +

"   Manager" +

" " +

"" +

"   Sara" +

"   Clerk" +

" " +

"";

try {

DocumentBuilderFactory dbf =

DocumentBuilderFactory.newInstance();

DocumentBuilder db = dbf.newDocumentBuilder();

InputSource is = new InputSource();

is.setCharacterStream(new StringReader(xmlRecords));

Document doc = db.parse(is);

NodeList nodes = doc.getElementsByTagName("employee");

// iterate the employees

for (int i = 0; i < nodes.getLength(); i++) {

Element element = (Element) nodes.item(i);

NodeList name = element.getElementsByTagName("name");

Element line = (Element) name.item(0);

System.out.println("Name:" + getCharacterDataFromElement(line));

NodeList title = element.getElementsByTagName("title");

line = (Element) title.item(0);

System.out.println("Title:" + getCharacterDataFromElement(line));

}

}

catch (Exception e) {

e.printStackTrace();

}

/*

output :

Name: John

Title: Manager

Name: Sara

Title: Clerk

*/

}

public static String getCharacterDataFromElement(Element e) {

Node child = e.getFirstChild();

if (child instanceof CharacterData) {

CharacterData cd = (CharacterData) child;

return cd.getData();

}

return"?";

}

}