使用for循环实现1到100的和
#include <stdio.h>int main(int argc, const char *argv[]){int i,sum = 0;for(i = 1;i < 100 ; i++){sum += i;}printf("sum = %d\n",sum);return 0;}
#include <stdio.h>
int main(int argc, const char *argv[])
{
int i,sum=0;
#if 0
//第一种----------------------------------------------------------
for(i=1; i<=100; i++){
sum+=i;
}
printf("sum = %d\n",sum);
//第二种----------------------------------------------------------
i=0;
for(;i<=100;i++){
sum+=i;
}
printf("sum = %d\n",sum);
//第三种----------------------------------------------------------
i=0;
for(;i<=100;){
sum+=i++;
}
printf("sum = %d\n",sum);
#endif
//第四种----------------------------------------------------------
i=0;
for(;;){
if(i>100)break;
sum+=i++;
}
printf("sum = %d\n",sum);//sum=5050
return 0;
}
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